Wednesday, May 5, 2010

Stupid math question of the day

Sometimes, there are questions that seem to be fairly simple, yet I can't find the answer anywhere:


Will a vector sublattice of a Riesz space generated by a finite set be finite-dimensional?

1 comment:

Aleksei said...

Actually, no.
Consider (1,1,1,...) and (1,1/2,1/3,...) in \ell_\infty (which is a second dual, hence order complete Banach lattice).